Linear Circuit Analysis
1. Introduction
2. Basic Concepts
- Currents and voltages
- Linear circuits
- Linear components
- Loops and nodes
- Series and parallel
- R, L & C combinations
- V & I combinations
- Power and energy
3. Simple Circuits
- Ohm's law
- Kirchhoff's current law
- Kirchhoff's voltage law
- Single loop circuits
- Single node-pair circuits
- Voltage division
- Current division
4. Nodal and Mesh Analysis
5. Additional Analysis Techniques
- Superposition
- Source transformation
- The $V_{test}/I_{test}$ method
- Norton equivalent
- Thévenin equivalent
- Max power transfer
6. AC Analysis
7. Operational Amplifiers
8. Laplace Transforms
9. Time-Dependent Circuits
- Introduction
- First-order transients
- Nodal analysis
- Mesh analysis
- Laplace transforms
- Additional techniques
10. Two-port networks
AC Power Analysis
Power analysis in time-domain domain
Consider the component shown in
and assume that $$\begin{equation}V(t) = V_M \cos(\omega t+\phi_V)\end{equation}$$ $$\begin{equation}I(t) = I_M \cos(\omega t+\phi_I)\end{equation}$$ where $V_M$, $I_M$, $\phi_V$, and $\phi_I$ are the magnitudes and phases of the voltage and current, respectively.The instantaneous power dissipated by the component is defined as $$\begin{equation}P(t)=V(t) I(t)=\frac{V_M I_M}{2} [\cos(\phi_V-\phi_I) + \cos(2\omega t + \phi_V +\phi_I)]\end{equation}$$
while the average power dissipated by the component is defined as $$\begin{equation}P=\frac{1}{2}V_M I_M \cos(\phi_V-\phi_I)\end{equation}$$ Notice that in a purely resistive load $P=\frac{V_M I_M}{2}$, while for ideal inductors and capacitors $P=0$.
We can also define the instantaneous power generated by the component as $-P(t)$ and the average power generated by it as $-P$.
The apparent power is defined as $P=\frac{V_M I_M}{2}$, while the power factor (pf) is ration of the average power to the apparent power $$\begin{equation}pf=\cos(\phi_V-\phi_I)\end{equation}$$ The power factor is a measure of the energy efficiency of the an AC equipment. The lower the power factor, the less efficient the power usage is. If an equipment is running with $pf<0.95$ is considered inefficient because of the ohmic losses in transmission lines.
Sometimes, it is convenient to write the powers in terms of the root-mean square (rms) value of the voltage and current, which are defined as$V_{rms}=\frac{V_M}{\sqrt{2}}$ and $I_{rms}=\frac{I_M}{\sqrt{2}}$. With these notations, the average power dissipated by the component is $$\begin{equation}P=V_{rms}I_{rms}\cos(\phi_V-\phi_I)\end{equation}$$
Power analysis in complex form
The average power, the apparent power and the power factor of a component can be computed relatively easy by using the formalism of complex analysis. To do so, it is instrumental to define the complex power absorbed by the compoenent as $$\begin{equation}S=\frac{1}{2}V I^*\end{equation}$$ where $V$ is the complex voltage, $I$ is the complex current, and $I^*$ denotes the complex conjugate of $I$. If the component is a complex impedance $Z$ the complex power can be computed by introducing Ohm's law in the previous equation, $S=\frac{1}{2} |I|^2 Z=\frac{|V|^2}{Z^*}$. Notice that, in the case of resistors, the complex power becomes a real number. Notice that we can also define the complex power supplied by the component as the negative of the power absorbed.
If the complex power is known, one can compute
- The average power $$P=Re(S)$$
- The reactive power $$Q=Im(S)$$
- The apparent power $$|S|=Abs(S)$$
- The power factor $$pf=\frac{Re(S)}{|S|}$$
Name | Notation | Units |
---|---|---|
Complex power | $S$ | volt-amperes, $\: \textcolor{gray}{VA}$ |
Apparent power | $|S|$ | volt-amperes, $\: \textcolor{gray}{VA}$ |
Average (real) power | $P$ | watts, $\: \textcolor{gray}{W}$ |
Reactive power | $Q$ | volt-amperes reactive, $\: \textcolor{gray}{VAR}$ |
Power factor | $pf$ |
Maximum average power transfer
Consider the circuit in
. If $V_{Th}$ and $Z_{Th}$ are specified and one can change the value of the load impedance, the maxium power transfer occurs when $$\begin{equation}Z_L=Z_{Th}^*\end{equation}$$ When this condition is satisfied $\cos(\phi_V-\phi_I)=1$ and the average power becomes maximum.In general, if the $V_{Th} - Z_{Th}$ circuit contains multiple impedances, voltage sources and current sources, it can always be replaced by its Thévenin equivalent circuit and we can still use the above equation to calculate the load impedance for which the average power transferred is maximum.
Notes
- The power triangle states that $$\begin{equation}\tan(\phi_V-\phi_I)=\frac{Q}{P}\end{equation}$$ which can be obtained from the definition of real and reactive powers.
- The rms value of a signal can be defined in general for any periodic waveform of the voltage or current as the DC voltage or current that dissipates the same amount of power as the average power dissipated by the time-varying voltage or current.
Sample Solved Problems
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AC power analysis
AC circuit with 2 independent sources and 2 impedances
AC circuit with 2 independent sources and 4 impedances
AC circuit with 2 independent sources, 1 dependent source, and 5 impedances -
AC maximum power transfer
2-loop circuit with 2 independent sources and 2 impedances
3-loop circuit with 2 independent sources and 4 impedances
3-loop circuit with 1 independent source, 1 dependent source and 5 impedances