Linear Circuit Analysis
1. Introduction
2. Basic Concepts
- Currents and voltages
- Linear circuits
- Linear components
- Loops and nodes
- Series and parallel
- R, L & C combinations
- V & I combinations
- Power and energy
3. Simple Circuits
- Ohm's law
- Kirchhoff's current law
- Kirchhoff's voltage law
- Single loop circuits
- Single node-pair circuits
- Voltage division
- Current division
4. Nodal and Mesh Analysis
5. Additional Analysis Techniques
- Superposition
- Source transformation
- The $V_{test}/I_{test}$ method
- Norton equivalent
- Thévenin equivalent
- Max power transfer
6. AC Analysis
7. Operational Amplifiers
8. Laplace Transforms
9. Time-Dependent Circuits
- Introduction
- First-order transients
- Nodal analysis
- Mesh analysis
- Laplace transforms
- Additional techniques
10. Two-port networks
The Method of Laplace Transform
Instead of writing the solving the system of nodal or mesh analysis in time-domain (which we saw that it leads to a system of integro-differential equations), it is often easier to transform the original circuit in the s-domain. Then, we solve the nodal or mesh analysis equations in the s-domain and, finally, take the invese Laplace transform to compute the sought variables in time-domain.
Notice that, the system of equations that we write for the new circuit (i.e. transformed in the s-domain) is exactly the same as the system of equations that we obtain by writting the nodal or mesh analysis equations in time-domain (using integro-differential equations) and taking the direct Laplace transform of thee equations. Therefore, if you learn the rules of converting a circuit to the s-domain, you are actually skipping two steps: writting the system of integro-differential equations and taking its Laplace transform.
Branch currents in the s-domain
When we write KCL in a nodal analysis, we need to express the branch currents in terms of the nodal potentials.
$$\begin{equation}u(t)=\begin{cases}0, & \text{if $t<0$}.\\1, & \text{otherwise}\end{cases}\end{equation}$$ describes how to write the currents going through different components in nodal analysis. In this table, $u(t)$ is the step functionName | Symbol | Branch current (s-domain) |
---|---|---|
Independent current source | $$\begin{equation}I(s)=\frac{I_0}{s}\end{equation}$$ | |
Resistor | $$\begin{equation}I(s)=\frac{V(s)}{R}\end{equation}$$ | |
Capacitor | $$\begin{equation}I(s)=sC\cdot V(s)-C\cdot V_{C}(0)\end{equation}$$ | |
Inductor | $$\begin{equation}I(s)=\frac{V(s)}{sL} + \frac{I_{L}(0)}{s}\end{equation}$$ |
For instance, the nodal equation in s-domain for node $v_{3}$ for the circuit represented in
$$\begin{equation}sC\cdot (v_{3}-v_{2}) - C\cdot V_{C0} + \frac{I_{L0}}{s} + \frac{v_3-v_5}{sL_1} + \frac{v_{3}-v_{2}}{R_{1}}=0\end{equation}$$ iswhere $I_{L0}$ is the current going through the inductor at $t=0$. Notice that the previous equation is valid for $t>0$. To simplify notations, we have not denoted explicitly that $v_1$,..., $v_5$ are functions of $s$, however, we should consider them as $v_1(s)$,..., $v_5(s)$.
Branch voltages in the s-domain
When we write KCL in a nodal analysis, we need to express the branch currents in terms of the nodal potentials.
describes how to write the currents going through different components in nodal analysis.Name | Symbol | Voltage |
---|---|---|
Independent voltage source | $$\begin{equation}V(s)=\frac{V_{0}}{s}\end{equation}$$ | |
Resistor | $$\begin{equation}V(s)=I(s){R}\end{equation}$$ | |
Capacitor | $$\begin{equation}V(s)=\frac{I(s)}{sC} + \frac{V(t_0)}{s}\end{equation}$$ | |
Inductor | $$\begin{equation}V(s)=sL\cdot I(s)-L\cdot I_{L}(0)\end{equation}$$ |
The mesh equation in s-domain for mesh current $i_{2}$ in the circuit represented in
$$\begin{equation}i_{2}R_{2}+\frac{V_{C0}}{s}+\frac{i_2-i_3}{sC_1} -V_1 -L\cdot I_{L0} + sL_1\cdot (i_{2}-i_{1})=0\end{equation}$$ iswhere $V_{C0}$ is the voltage across the capacitor at $t=0$. Notice that the previous equation is valid for $t>0$, where $i_1$, $i_2$, and $i_3$ are functions of $s$.
Algorithm
The algorithm for writting the nodal or mesh analsyis equations in the s-domain is the same as in the DC, AC, or time-dependent case. You can click the links below to see examples on how we write and solve the nodal and mesh analysis equations in the s-domain.
Sample Solved Problems
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Nodal analysis in the s-domain
TD circuit solved using Laplace tranforms (1 storage element)
TD circuit solved using Laplace tranforms (2 storage elements)
Mesh analysis in the s-domain
TD circuit solved using Laplace tranforms (1 storage element)
TD circuit solved using Laplace tranforms (2 storage elements)