Linear Circuit Analysis
1. Introduction
2. Basic Concepts
- Currents and voltages
- Linear circuits
- Linear components
- Loops and nodes
- Series and parallel
- R, L & C combinations
- V & I combinations
- Power and energy
3. Simple Circuits
- Ohm's law
- Kirchhoff's current law
- Kirchhoff's voltage law
- Single loop circuits
- Single node-pair circuits
- Voltage division
- Current division
4. Nodal and Mesh Analysis
5. Additional Analysis Techniques
6. AC Analysis
7. Operational Amplifiers
8. Laplace Transforms
9. Time-Dependent Circuits
- Introduction
- First-order transients
- Nodal analysis
- Mesh analysis
- Laplace transforms
- Additional techniques
10. Two-port networks
Norton's' Theorem
Norton's theorem states that any two-terminal linear circuit containing only voltage sources, current sources and resistors (or impedances in the case of AC circuits) can be replaced by an equivalent combination of a current source $I_{N}$ in parallel with a resistor $R_{N}$ (or impedance $Z_{N}$ in the case of AC circuits).
Norton's theorem and its dual, Thévenin's theorem, are widely used to simplify circuit analysis and study a circuit's initial-condition and steady-state response. Norton's theorem may in some cases be more convenient to use than Kirchhoff's circuit laws when analyzing linear circuits.
Calculating the Norton equivalent circuit
Calculating the Norton equivalent circuit, or simply Norton equivalent of a circuit with two terminals means computing the Norton current and Norton resistance of the circuit.
The Norton current can be computed using any of the following methods:
- $I_{N} = I_{s.c}$ - the Norton current is equal to the short-circuit current at the output terminals of the original circuit. To compute $I_{s.c.}$ one can use any of the methods of linear circuit analysis such as nodal analysis, mesh analysis, or current and voltage division.
- If the Thévenin voltage $V_{Th}$ and Thévenin resistance $R_{Th}$ are known and $R_{Th} \neq 0$, one can calculate the Norton current using $I_{N} = V_{Th}/R_{Th}$ .
The Norton resistance can be computed using any of the following methods:
- $R_{N}$ can be computed by deactivating all independent sources and using the test voltage or test current methods using Ohm's law, $R_{N}=\frac{V_{test}}{I_{test}}$. To use the test voltage method, we connect a test voltage source at the output terminals (usually, but not necessarily, taken as $V_{test}=1~V$) and compute current $I_{test}$. To use the test current method, we connect a test current source at the output terminals (usually, but not necessarily, taken as $I_{test}=1~A$) and compute voltage $V_{test}$.
- If the circuit does not contain any dependent sources, $R_{N}$ can be computed by deactivating all independent sources and looking at the resistance seen from the output terminals (in this case, $R_{N}$ can often be computed using series and parallel simplifications of resistors).
- If Norton current $I_N$ and Thévenin voltage $V_{Th}$ are known and $I_{N} \neq 0$, one can calculate the Norton resistance using $R_{N} = \frac{V_{Th}}{I_{N}}$.
Notes
- Sometimes, the Norton voltage and Norton resistance can be computed simultaneously by performing successive source transformations and using series and parallel combinations of resistors, voltage sources and current sources.
- The Noton current of a circuit that does not contain any independent voltage and current sources is always 0.
- The Thévenin and Norton resistances, the Thévenin voltage and the Norton current satisfy the following relationships: $$\begin{equation}R_{Th}=R_N\end{equation}$$ $$\begin{equation}V_{Th}=I_N R_{Th}\end{equation}$$Because of these relationships, it is usually necessary to find only two quantities because the other two can be calculated afterwards.
- To deactivate a current source we remove it from the circuit (replace it with open-circuit or break); to deactivate a voltage source we replace it with a short-circuit (or wire).
- The above techniques can also be used to compute the Norton current and Norton impedance $Z_{N}$ in linear AC circuits.